Three men A, B and C working together can do a job in 6 hours less time than A alone, in 1 hour less time than B alone and in one half the time needed by C when working alone. Within how much time can A and B together do the job?
Let's denote the time it takes for A to complete the job alone as "a", the time it takes for B to complete the job alone as "b", and the time it takes for C to complete the job alone as "c".
From the problem, we can write the following equations:
- 3(a-6) = a
- 3(b-1) = b
- 3(c/2) = c
Simplifying these equations, we get:
- 2a - 18 = 3a => a = 18
- 2b - 3 = b => b = 3
- 3c/2 = c => c = 2
This means that A can complete the job alone in 18 hours, B can complete the job alone in 3 hours, and C can complete the job alone in 2 hours.
Now, let's find the time it takes for A, B, and C to complete the job together. We can use the formula:
1/Time taken by A,B and C together = 1/A + 1/B + 1/C
Substituting the values we obtained above, we get:
1/Time taken by A and B together = 1/18 + 1/3
Simplifying this equation, we get:
1/Time taken by A and B together = 5/18
Therefore, the time taken by A and B together to complete the job is:
Time taken by A and B together = 18/5 hours
So, A and B together can complete the job in 3.6 hours.
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